Start the machine, hack the system, and find the hidden flags to complete this challenge and earn points!

1
Flags
5
Points
87%
Success Rate
Start Your Challenge
~1-2 min setup
Dedicated server
Private instance
Industry standard
This solution is for Flags Mode

This walkthrough explains how to hack the lab and capture the flags. For help with Learning Mode questions, use the Request Hint button next to each question.

Challenge

Solution Steps

1. Understanding the Challenge

The challenge presents a binary file with a hidden flag embedded within random data. The flag is stored as a string with a length indicator and marker.

2. Initial Analysis

Start by examining the file with basic tools:

Method 1: Using the strings command

strings secret_binary.bin

This will show you the printable strings in the file, including the flag and the "END_FLAG" marker.

Method 2: Using xxd for hex dump

xxd secret_binary.bin

This will show you the raw hexadecimal representation of the file.

3. Analyzing the File Structure

The binary file has the following structure:

  1. 100 bytes of random data
  2. 4-byte integer indicating the flag length
  3. The flag string itself
  4. 200 bytes of random data
  5. "END_FLAG" marker (8 bytes)
  6. 50 bytes of random data

4. Extracting the Flag

Method 1: Using Python

import struct

with open('secret_binary.bin', 'rb') as f:
    # Skip 100 bytes of random data
    f.seek(100)
    
    # Read the flag length (4-byte integer)
    flag_length = struct.unpack('I', f.read(4))[0]
    
    # Read the flag
    flag = f.read(flag_length).decode('utf-8')
    
    print(f"Flag: {flag}")

Method 2: Using hex editor

  1. Open the file in a hex editor (HxD, 010 Editor, etc.)
  2. Navigate to offset 100 (0x64 in hex)
  3. Read the next 4 bytes as a little-endian integer
  4. This gives you the flag length
  5. Read the next N bytes (where N is the flag length) as ASCII text

Method 3: Using command line tools

# Extract the flag length
hex_length=$(xxd -p -s 100 -l 4 secret_binary.bin | tr -d '\n')
# Convert from little-endian hex to decimal
length=$((16#$(echo $hex_length | rev | sed 's/\([0-9a-f]\)\([0-9a-f]\)\([0-9a-f]\)\([0-9a-f]\)/\4\3\2\1/' | rev)))
# Extract the flag
flag=$(dd if=secret_binary.bin bs=1 skip=104 count=$length 2>/dev/null)
echo "Flag: $flag"

5. Getting the Flag

The flag is: 85fab29d-d6c6-4373-8a87-db3b83711b3a

6. Verification

To verify the solution:

  1. The flag should be a valid UUID format
  2. It should be exactly 36 characters long
  3. It should be located after the length indicator at offset 100
  4. The "END_FLAG" marker should appear after the flag

7. Technical Details

  • The file contains 100 bytes of random data at the beginning
  • The flag length is stored as a 4-byte little-endian integer at offset 100
  • The flag is stored as a UTF-8 string starting at offset 104
  • 200 bytes of random data follow the flag
  • The "END_FLAG" marker (8 bytes) indicates the end of the flag section
  • 50 bytes of random data complete the file

8. Learning Points

  • Binary files can contain structured data with length indicators
  • Understanding data types and byte order is crucial for binary analysis
  • Tools like strings can quickly reveal hidden text data
  • Hex editors provide detailed view of binary file contents
  • Pattern recognition helps identify data structures in binary files

9. Alternative Approaches

If the above methods don't work, you can also:

  • Use binwalk to analyze the file structure
  • Use objdump if the file is an executable
  • Write a custom script in any programming language
  • Use online hex analysis tools

10. Security Implications

This challenge demonstrates several important concepts:

  • Data can be hidden in seemingly random binary files
  • Understanding file structure is essential for forensic analysis
  • Length indicators and markers help organize binary data
  • Binary analysis skills are crucial for malware analysis and reverse engineering